General Riddles

As I was going to the mall I met a man with seven wives, Each wive held two bags, Each bag held a mother cat, Each mother cat had six babies, How many people where going to the mall?
One! As I was going to the mall I met a man...

Place a word with 4 letters in between the two words so that it can be used as a prefix and suffix to make two new words. SPOILS_______ION

A man is pushing his car along the road when he comes to a hotel. He shouts, "I'm bankrupt!" Why?
He was playing Monopoly.

Use the word "dormitory" to make two words which will complete the below sentence. Daniel stays in a _______ _______.
dirty room

End always begins with me. Time, space and universe always end with me. Who am I?
The letter 'E'.

A shepherd has 18 goats. All but 6 die. How many are left?
6 of course!

Adam is 13 years old in 1980. In 1985 he is 8 years old. How?
The dates are in BC (Before Christ).

In a cave there is a treasure within a big metal box with a lock on it. There is also a monster in the cave that has two keys with him; one gold and the other silver. The monster will give you only one chance to open the lock using one of the keys. If the box doesn't open, the monster will kill you. Since the monster is a bit helpful it would give you a clue in finding out the correct key. Can you choose the correct key by deciphering the below clue? A GKOY OEPD LYEO DCNO EAAR NNN
The gold key will open the lock. Explanation: The clue says "A Golden Key Can Open Any Door". Take the first letter of each word, then the second letter of each word, then the third letter and so on and construct the sentence.

I am an eight letter word. My first four letters combine to form an atmospheric state. My third, fourth, fifth, sixth and seventh letters give support. My last three letters is the name of a person. Who am I?
MISTAKEN

I am in the beginning of sorrow and sadness. You will find me in happiness also. You will find me in sun and stars but not in moon. I am in summer and spring but not in fall or winter. Who am I?
The alphabet S.

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